1 .- We play a lot simpler, because when it comes zero is more advantageous to lose half the bet.

2 .- Assume that the times earned less than the losses (to cover us with this bad bouts against us). So try to recover liabilities with a lower number of times to the losses (ie half).

3 .- It must be simple in its execution.

We expect a first indication of play and assume that the other lot will come out at least half the time. Therefore, we have to recover with half times the lot by playing against the former. We will create a passive initial 1, which is the gain we want to achieve.

That is, for 1 .. 2 losses be recovered in 1 to fall to 3 .. 4, 2 to 5 .. 6 3. Therefore, every time we get a recovery we have to cross out two losses, by crossing out the top and the remaining groups of two gambling losses, we will indicate recoveries.

Example :

Num … … Stay … Bet … … Total

1 … … … …. N … … … … … … … … … … … … … … … .. 1 Here we have a group to recover from (N, ..) so we’ll do 1R

2 … … … …. N … … … … … … … 1R … … … … … 2 … … .. Here we have an entire group (N, N) and the recovery will remain at 1.

3 … … … …. N … … … … … … … 2R … … … … … 4 … … .. So far it has gone 3 N, therefore we have (N, N) (N ,..). Therefore we expect an R by the first group and another by the second. Divide the liability therefore, by 2.

4 … … … …. N … … … … … … … 2R … … … … … 6 … … .. Here we have two groups of two losses each, so we still wish to recover in two attempts.

5 … … … …. N … … … … … … … 3R … … … … … 9 … … .. Already we 5N consecutive therefore we will have (N, N) (N, N) (N, ..) and for each expect an R or 3R, therefore liabilities divided by 3

6 … … … …. N … … … … … … … 3R … … … … … … .. 12. We still have three groups (N, N) (N, N) (N, N) therefore recoveries will be 3.

7 … … … …. A … … … … … … … 4R … … … … … 8 … … .. Here we have recovered a group branded by both two N starting with the principle (that is the no.1 and no.2) and we will be two groups (N, N) (N, N) therefore again try to recover in 2R.

8 … … … …. N … … … … … … … 4R … … … … … … .. 12. Lost recovery, we now have (N, N) (N, N) (N, ..) and we have to recover in 3R

9 … … … …. A … … … … … … … 4R … … … … … 8 … … .. Has picked a couple, we have (N, N) (N, ..) and recover in two

10 … … … .. R … … … … … … … 4R … … … … … 4 … … .. Has recovered another couple, now we will have (N, ..) to recover.

11 … … … .. R … … … … … … … 4R … … … … … 0 … … .. Was completed, and the gain was 1 initial start again now.

We see that the number of R is 4 while blacks are 7.

When there is only zero to update the Total and nothing more

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