Is to gamble 4 chips to 2 dozen and a card to a group of 4 numbers (box), this would cover 28 numbers. If you go to one of the numbers of group 4 is not lost nor won (table). If you quit one of the number of 2 dozen earn 3.

Example Wager

First Dozen Bet 4
4 Second Dozen Bet
Bet 1 group of four numbers

As Gambling

4 chips to be bet Dozens Two and a tab to a group of four numbers.
This will cover 28 numbers.
If you go to one of the numbers of Group Four is not lost or won.

If you leave a number of the two dozen earn 3 cards per hand.

How to choose the 2 dozen

Must see what is going on the board, or the last two numbers.

Repeat the last two played dozens, if in this case returns to repeat the same dozen, then do not gamble. We must wait for the spinner to break the trend of playing the same dozen.
When this occurs should be continued with the method of betting the last two dozen.
Zeros are not considered in this method

This method is based on the assumption that the wheel does not play perfectly, osea
Three dozen repeating Example:

First, Second and Third dozen
Second, First and Third Dozen
Most often it is the opposite.

VARIANTS
Hi,

I enclose a variant of the system Romanosky.

The alternative is simple and only vary the amounts.
Instead of the 4 dozen bet, bet 3.
Ie, 3 +3 = 6 bet tokens for two dozen, 1 +1 and two groups of 4.
This will cover 32 numbers. Any of the numbers correct gives a profit of 1 tab.
If not get lost 3 +3 +1 +1 = 8 chips.
In the original system there are twice as likely not to succeed, as are single issues 8 and 9 run loss in the chips.
In this variant, 4 numbers are taken down (plus zero!) And 8 chips lost if no hit.

Another variant: bet 14 chips in total.

Bet 5 chips to the dozen (5 +5 = 10)
and the other 4 tabs (where to get the win 1 dozen tab) Cover 2 groups of 4 and two groups of 2.
In this case we therefore in total 14 cards!
if the right wins dozen 1 tab.
If any group of 2 hits, 3 earned tokens.
If a “hit” some groups of 4, lost 5 chips!
The chances of losing are als same as the original system, but the losses are smaller, there are 4 +4 +1 = 9, here are 9-14 = 5

The latest variant:

6 dozen each (12 sheets), gives 18 cards wisely.
5 bet more chips to distribute:
2 chips in 2 groups of 4
1 sheet in 1 group 2
It covers 34 numbers (excluding zero !!!), only 2 single issues.
You always win 1 chip (since in all cases received 18 cards and 17 bets)

If you do not want to risk losing 18 tokens in one go if you leave any of the 2 issues are not covered (not to mention zero, which is always hung up) you can start to climb to 12 dozen.
So bet on the dozens 12 +12, 2 +2 +2 3 groups of 2, and 5 1 group of 6, a total of 35 chips.
If you leave the dozens of one or any number of group 2 wins +1 tab.
If a group number 6, lost 5 chips.

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